{"id":5884,"date":"2025-07-15T13:34:45","date_gmt":"2025-07-15T13:34:45","guid":{"rendered":"https:\/\/functiontranslator.com\/xor\/"},"modified":"2021-02-26T10:06:10","modified_gmt":"2021-02-26T10:06:10","slug":"xor","status":"publish","type":"post","link":"https:\/\/functiontranslator.com\/cs\/xor\/","title":{"rendered":"XOR"},"content":{"rendered":"<h2>P\u0159ehled a syntaxe<\/h2>\n<p>Funkce XOR pat\u0159\u00ed mezi logick\u00e9 funkce dostupn\u00e9 v MS Excel a Google Sheets. Tato funkce realizuje operaci <em>exkluzivn\u00ed OR<\/em>, \u010dasto pou\u017e\u00edvanou v logick\u00fdch v\u00fdpo\u010dtech. Vrac\u00ed hodnotu <strong>TRUE<\/strong>, pokud je po\u010det argument\u016f s hodnotou TRUE nep\u00e1rn\u00fd, a <strong>FALSE<\/strong>, pokud je tento po\u010det p\u00e1rn\u00fd nebo nulov\u00fd. Funkce XOR nach\u00e1z\u00ed uplatn\u011bn\u00ed v anal\u00fdz\u00e1ch a v\u00fdpo\u010dtech, kde je d\u016fle\u017eit\u00e1 specifick\u00e1 kombinace podm\u00ednek.<\/p>\n<p><strong>Syntaxe funkce v Excelu a Google Sheets:<\/strong><\/p>\n<pre><code>=XOR(logick\u00e1_hodnota1, [logick\u00e1_hodnota2, ...])<\/code><\/pre>\n<p>Ka\u017ed\u00fd argument m\u016f\u017ee p\u0159edstavovat bu\u010f p\u0159\u00edmo logickou hodnotu (TRUE nebo FALSE), nebo jak\u00fdkoliv v\u00fdraz, kter\u00fd logickou hodnotu vrac\u00ed. V jednom vol\u00e1n\u00ed funkce XOR m\u016f\u017eeme pou\u017e\u00edt a\u017e 255 logick\u00fdch hodnot nebo pol\u00ed hodnot.<\/p>\n<h2>P\u0159\u00edklady pou\u017eit\u00ed v praxi<\/h2>\n<p>Uve\u010fme dva praktick\u00e9 p\u0159\u00edklady, jak lze funkci XOR vyu\u017e\u00edt.<\/p>\n<h2>1. Vy\u0159e\u0161en\u00ed konfliktn\u00edch podm\u00ednek<\/h2>\n<p>P\u0159edpokl\u00e1dejme, \u017ee m\u00e1me seznam zam\u011bstnanc\u016f, kte\u0159\u00ed bu\u010f pracuj\u00ed na pln\u00fd \u00favazek, nebo jsou na mate\u0159sk\u00e9\/popat\u0159i\u010dn\u00e9 dovolen\u00e9. C\u00edlem je identifikovat ty, co jsou bu\u010f na pln\u00e9m \u00favazku nebo na dovolen\u00e9, av\u0161ak nikoliv ob\u011b sou\u010dasn\u011b.<\/p>\n<pre><code>=XOR(B2, C2)<\/code><\/pre>\n<p>Tabulka pro demonstraci:<\/p>\n<table>\n<tr>\n<th>Jm\u00e9no<\/th>\n<th>Na pln\u00fd \u00favazek<\/th>\n<th>Na dovolen\u00e9<\/th>\n<th>V\u00fdsledek XOR<\/th>\n<\/tr>\n<tr>\n<td>Jan Nov\u00e1k<\/td>\n<td>TRUE<\/td>\n<td>FALSE<\/td>\n<td>TRUE<\/td>\n<\/tr>\n<tr>\n<td>Petr S\u00fdkora<\/td>\n<td>FALSE<\/td>\n<td>TRUE<\/td>\n<td>TRUE<\/td>\n<\/tr>\n<tr>\n<td>Lucie \u0160\u00edpov\u00e1<\/td>\n<td>TRUE<\/td>\n<td>TRUE<\/td>\n<td>FALSE<\/td>\n<\/tr>\n<tr>\n<td>Marta Kr\u00e1lov\u00e1<\/td>\n<td>FALSE<\/td>\n<td>FALSE<\/td>\n<td>FALSE<\/td>\n<\/tr>\n<\/table>\n<p>Kde hodnota <strong>TRUE<\/strong> ve sloupci &#8222;V\u00fdsledek XOR&#8220; zna\u010d\u00ed, \u017ee zam\u011bstnanec spl\u0148uje jednu z podm\u00ednek, ale ne ob\u011b najednou.<\/p>\n<h2>2. Logick\u00e1 hra pro v\u00edce hr\u00e1\u010d\u016f<\/h2>\n<p>P\u0159edstavme si hru, kde hr\u00e1\u010di odpov\u00eddaj\u00ed Ano (TRUE) nebo Ne (FALSE) na ot\u00e1zky. C\u00edlem je, aby vyhr\u00e1l ten hr\u00e1\u010d, kter\u00fd zvolil odpov\u011b\u010f odli\u0161nou od v\u011bt\u0161iny. Pokud t\u0159i hr\u00e1\u010di odpov\u00ed a pou\u017eijeme funkci XOR, v\u00fdsledek bude <strong>TRUE<\/strong> pouze tehdy, kdy\u017e p\u0159esn\u011b jeden hr\u00e1\u010d odpov\u00ed Ano.<\/p>\n<pre><code>=XOR(D2, E2, F2)<\/code><\/pre>\n<p>Tabulka pro demonstraci:<\/p>\n<table>\n<tr>\n<th>Hr\u00e1\u010d 1<\/th>\n<th>Hr\u00e1\u010d 2<\/th>\n<th>Hr\u00e1\u010d 3<\/th>\n<th>V\u00fdsledek XOR<\/th>\n<\/tr>\n<tr>\n<td>TRUE<\/td>\n<td>FALSE<\/td>\n<td>FALSE<\/td>\n<td>TRUE<\/td>\n<\/tr>\n<tr>\n<td>TRUE<\/td>\n<td>TRUE<\/td>\n<td>FALSE<\/td>\n<td>FALSE<\/td>\n<\/tr>\n<tr>\n<td>FALSE<\/td>\n<td>FALSE<\/td>\n<td>FALSE<\/td>\n<td>FALSE<\/td>\n<\/tr>\n<tr>\n<td>TRUE<\/td>\n<td>TRUE<\/td>\n<td>TRUE<\/td>\n<td>FALSE<\/td>\n<\/tr>\n<\/table>\n<p>V tomto p\u0159\u00edpad\u011b znamen\u00e1 hodnota <strong>TRUE<\/strong> ve sloupci &#8222;V\u00fdsledek XOR&#8220; to, \u017ee pr\u00e1v\u011b jeden hr\u00e1\u010d odpov\u011bd\u011bl odli\u0161n\u011b a z\u00edsk\u00e1v\u00e1 bod.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Vr\u00e1t\u00ed hodnotu logick\u00e9 operace XOR pro v\u0161echny argumenty<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[285],"tags":[],"class_list":["post-5884","post","type-post","status-publish","format-standard","hentry","category-logicke"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v23.8 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Funkce XOR v Excelu: jak funguje, primjeri kori\u0161tenja formule<\/title>\n<meta name=\"description\" content=\"Opis funkcije XOR u Excelu i Google tablicama. 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